{"content":{"sharePage":{"page":0,"digests":[{"id":"30367785","dateCreated":"1290013412","smartDate":"Nov 17, 2010","userCreated":{"username":"alaxei","url":"https:\/\/www.wikispaces.com\/user\/view\/alaxei","imageUrl":"https:\/\/ssl.wikicdn.com\/i\/user_none_lg.jpg"},"monitored":false,"locked":false,"links":{"self":"https:\/\/zestawy.wikispaces.com\/share\/view\/30367785"},"dateDigested":1532389870,"startDate":null,"sharedType":"discussion","title":"Zadanie #5","description":"Mam pytanie:<br \/>\nOdnalaz\u0142em mas\u0119 cia\u0142a m=F\/a=2N\/0.5ms2=4kg<br \/>\nNa cia\u0142o zacz\u0119\u0142a dzia\u0142a\u0107 tak\u017ce si\u0142a F2, ale gdy spr\u00f3bowa\u0142em doda\u0107 F1 i F2 to otrzyma\u0142em pierwiastek z 13. Prosz\u0119 o pom\u00f3c.","replyPages":[{"page":0,"digests":[{"id":"31194685","body":"Nie zauwa\u017cy\u0142em tego postu. Prosz\u0119 pisa\u0107 na ret25tdk@wp.pl. Pierwiastek z liczby 13 istnieje:). Kalkulator policzy i poka\u017ce \u017ce pierwiastek z 13 r\u00f3wna si\u0119.... :). Pozdrawiam serdecznie. TM.","dateCreated":"1291553658","smartDate":"Dec 5, 2010","userCreated":{"username":"sjpdc-fizyka","url":"https:\/\/www.wikispaces.com\/user\/view\/sjpdc-fizyka","imageUrl":"https:\/\/www.wikispaces.com\/user\/pic\/1289164988\/sjpdc-fizyka-lg.jpg"}}],"more":0}]}],"more":false},"comments":[]},"http":{"code":200,"status":"OK"},"redirectUrl":null,"javascript":null,"notices":{"warning":[],"error":[],"info":[],"success":[]}}